I How Does the Einstein Equivalence Principle Explain Energy Source Curvature?

Frank Castle
Messages
579
Reaction score
23
TL;DR Why does the Einstein equivalence principle imply that all forms of (non-gravitational) energy source curvature?

Now, as understand it, the Einstein equivalence principle (EEP) implies (or at least suggests) that gravity is the manifestation of spacetime curvature, the reason being that it is impossible to locally distinguish, through conducting any non-gravitational experiment, between inertial acceleration and acceleration due to the presence of a gravitational field. As a consequence, all non-gravitational forms of energy will fall at the same rate in a gravitational field. This observation suggests that the curved trajectories of energy in a gravitational field is due to geometric nature of spacetime itself, and not due to a force, i.e. spacetime is curved.

We know from Newtonian gravity that mass sources gravity and thus, if gravity is the manifestation of spacetime curvature, the presence of mass must curve spacetime.

I’ve read that the EEP implies that all forms of non-gravitational energy source curvature, but I don’t understand why this is so?

I thought that it was simply due to the consequence of mass-energy equivalence from special relativity that energy sources curvature?!

Is the point that the weak equivalence principle neglects other contributions to mass energy (e.g. electromagnetic binding energy) and so in principle it could be that mass sources curvature, but that the electromagnetic binding energies etc. do not, and so would respond differently in a gravitational field. However, the EEP claims that all forms of energy couple to gravity in the same way and so they must also be considered sources of curvature?!
 
Last edited:
Physics news on Phys.org
Frank Castle said:
I’ve read that the EEP implies that all forms of non-gravitational energy source curvature

Where did you read this? Please give a reference. (And if the reference is not a textbook or peer-reviewed paper, please be ready to be told that it's not a valid reference and you should go read a textbook or peer-reviewed paper.)
 
PeterDonis said:
Where did you read this? Please give a reference. (And if the reference is not a textbook or peer-reviewed paper, please be ready to be told that it's not a valid reference and you should go read a textbook or peer-reviewed paper.)

Sorry for the delayed response. I’ve been reading these notes on the cosmological constant problem: https://arxiv.org/pdf/1502.05296.pdf

However, when (classical) gravity is switched on the equivalence principle tells us that all forms of energy curve spacetime[...]

It’s just a short sentence at the bottom of page 3, but it has left me confused.
 
Frank Castle said:
I thought that it was simply due to the consequence of mass-energy equivalence from special relativity that energy sources curvature?!

Careful here. The equivalence you speak of is between mass and rest energy.
 
SiennaTheGr8 said:
Careful here. The equivalence you speak of is between mass and rest energy.
Good point.

So what is the motivation for why all forms of (non-gravitational) energy source curvature? Is it simply that we know from Newtonian gravity that mass sources the gravitational field. If gravity is simply the manifestation of spacetime curvature, then mass must source curvature (locally). Then by the EEP we know that all forms of (non-gravitational) energy must couple to gravity identically (otherwise we would be able to detect whether we are in local uniform acceleration, or in a gravitational field simply by carrying out experiments involving different non-gravitational phenomena), and so these must also source local spacetime curvature?
 
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
Back
Top