How Does Energy Transfer Affect Temperature and Work in Gas Processes?

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In the discussion, a 1.00 mol sample of an ideal monatomic gas at 300 K undergoes an isovolumetric process, gaining 500 J of energy, which increases its internal energy. During the subsequent isobaric process, the gas loses the same amount of energy, leading to a question about the new temperature and work done on the gas. The internal energy change is linked to the heat transfer and work done, with the internal energy depending on temperature. The challenge lies in determining the pressure to calculate the work, as the relationship between internal energy and temperature is crucial. Understanding these principles is essential for solving the problem effectively.
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A 1.00 mol sample of an ideal monatomic gas is at an initial temperature of 300 K. The gas undergoes an isovolumetric process acquiring 500 J of energy by heat. It then undergoes an isobaric process losing this same amount of energy by heat. Determine a) the new temperature of the gas and b) the work done on the gas.

Ok...so for part A, I know since its undergoes isovolumetric process that the internal energy equals Q. So the internal energy is at 500 J at that point. Also, when it undergoes isobaric process, I know that the internal energy equals Q + W, where W is the work. The problem says it lost 500 J by heat so internal energy = 500 J - 500 J + W because there was 500 J from the previous process. So, internal energy = W. W = P* change in volume, so how could i get the pressure?

Any help is great thx!
 
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Hint: How does the internal energy of an ideal monatomic gas depend on temperature?
 
Thanks a lot !
 
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