How Does Friction Affect the Acceleration of Stacked Blocks?

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The discussion focuses on the dynamics of two stacked blocks where the top block slips on the lower block due to an applied force. The normal force acting on the lower block is determined by the combined weight of both blocks, leading to a frictional force calculated using the coefficient of kinetic friction. The resulting acceleration of the lower block is derived from the equation F - (frictional force) = m2 * a. A key point is the need to account for the friction force from the top block when calculating the overall acceleration. The correct formula for the acceleration of the lower block incorporates this additional frictional force.
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Homework Statement


A block of mass m1 is on top of a block of mass m2. The lower block is on a horizontal surface, and a rope can pull horizontally on the lower block. The coefficient of kinetic friction for all surfaces is μ. What is the resulting acceleration of the lower block if a force F is applied to the rope? Assume that F is sufficiently large so that the top block slips on the lower block.

Homework Equations



F = ma
Frictional Force = Normal Force * μ

The Attempt at a Solution



Normal Force (for lower block) = (m1 + m2) g
Frictional Force (for lower block) = μ * (m1 + m2) g
F - (μ * (m1 + m2) g) = m2 * a
a = ((F - (μ * (m1 + m2) g)) / m2

Correct Answer should be: a2 = (F - μg(2m1 + m2)) / m2
 
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welcome to pf!

hi vjnmath! welcome to pf! :smile:
vjnmath said:
… Assume that F is sufficiently large so that the top block slips on the lower block.

… sooo, you'll need to include the friction force from the top block :wink:
 
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