How Does Gauss's Law Apply to Nested Spherical Shells with Charges?

AI Thread Summary
Gauss's Law is applied to a system of nested conducting spherical shells with charges, where the inner shell has a charge of -3Q and the outer shell has +5Q. For regions inside the inner shell and outside the outer shell, the electric field is zero. Between the inner and outer surfaces of the shells, the electric field can be determined using Gauss's Law, which involves calculating the surface charge densities on both shells. The discussion emphasizes the importance of showing work and applying Gauss's Law correctly to find the electric field in different regions. Understanding these principles is crucial for solving the problem effectively.
stroperica
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Homework Statement


A small conducting spherical Shell (#1) with inner radius a and outter radius b is concentric with a larger conducting spherical shell (#2) with inner radius C and outter radius d. The inner shell has a total charge (-3Q), and outter shell has a charge ( +5 Q).

a) Use Gauss's law to find the electric field ( magnitude and direction) in terms of Q and r for

i) r<a;
ii) a<r<b;
iii) b<r<c;
iiii) c<r<d;

b) determine the surface charge density on the inner and outer surfaces of both shells.








The Attempt at a Solution



Electric field for i and iii is zero?
 
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Here is the figure for the exercise.
THANK YOU!
 
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stroperica said:

The Attempt at a Solution



Electric field for i and iii is zero?

Can you show your work? You are supposed to make use of Gauss's law here.
 
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