How does gravity and friction affect work on a slanted surface?

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The discussion focuses on calculating the work done by gravity and friction on a slanted surface. Gravity's work is expressed as Lsin(θ)mg, while friction's work is Lcos(θ)mgμ1. It is clarified that friction is a phenomenon resulting from gravity, which acts straight down, while the friction force is parallel to the ramp's surface. To find the total energy spent, both gravitational and frictional work must be added together, without creating energy from nothing. The conversation also notes a technical issue with the website affecting the discussion.
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Work, friction and gravity

Homework Statement



pic.png

Calculate the work done on the slanted portion by gravity and friction


Homework Equations



The Attempt at a Solution



Work is Fdx

F:
Gravity is L\sin\left(\theta\right)mg
Friction is L\cos\left(\theta\right)mg\mu_{1}

dx:
Friction travels along a path L, but is this also true for gravity?

Simply squaring the L's and adding them together, or subtracting friction, registers as incorrect.
 
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You already calculated the work done by gravity and friction. as you said
Gravity is Lsin(θ)mg
Friction is Lcos(θ)mgμ1

Friction doesn't travel, friction is a phenomenon caused by gravity, gravity always acts "straight down". The vector of the force of friction is parallel to the ramp's surface, yes. mg sin(a) is the ramp directional component of the force of gravity (imagine it as an invisible rope being pulled by invisible somebody).

assuming L is the distance the block travels down the ramp, then the above are the work done by the respective forces.

If you wanted to find out the total energy spent in this process, then you would have to add them together, don't create energy out of nothing, though.
 
Not sure why I rambled about squaring the L's.
There was a problem with the website, I hate those digital things.
Thanks anyway.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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