How Does Gravity on Planet Zircon Compare to Earth?

AI Thread Summary
The discussion revolves around calculating the acceleration of gravity on the planet Zircon based on the motion of a rock tossed horizontally by an astronaut. The rock is thrown at a speed of 6.55 m/s, falls 1.20 m vertically, and lands 8.60 m away horizontally. To find the acceleration due to gravity (Z), the time of flight is first calculated using the horizontal distance and initial speed. The formula y = 1/2*g*t² is adapted to derive Z as Z = 2*1.2*(v/d)². The conversation emphasizes the need to determine time from the given parameters to solve for gravity on Zircon.
wadini
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An astronaut on the planet Zircon tosses a rock horizontally with a speed of 6.55 m/s . The rock falls through a vertical distance of 1.20 m and lands a horizontal distance of 8.60 m from the astronaut. What is the acceleration of gravity on zicron?

I have no idea how to even start.
 
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i think x may be 8.60
 


okay so what I am thinking is that the Vinitial is 6.55 m/s and x=8.60 and form there I can find time
 


so I know I have to find time and then from there I can find acceleration but I don't know how to find time from what is given..?
 


wadini said:
An astronaut on the planet Zircon tosses a rock horizontally with a speed of 6.55 m/s . The rock falls through a vertical distance of 1.20 m and lands a horizontal distance of 8.60 m from the astronaut. What is the acceleration of gravity on zicron?

I have no idea how to even start.

On Earth it's

y = 1/2*g*t2

The time can be determined from

d/v = t

So on Zircon ...

1.2m = 1/2*Z*(d/v)2

or Z = 2*1.2*(v/d)2
 

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