How Does Inserting a Dielectric Affect Voltage in an Uncharged Capacitor?

AI Thread Summary
Inserting a dielectric into an uncharged capacitor decreases the voltage because it reduces the net electric field between the conductors. The presence of the dielectric increases the capacitance while keeping the charge constant, leading to a lower voltage according to the formula V=Q/C. This phenomenon is also influenced by the dielectric's properties, specifically its polarization, which further contributes to the decrease in voltage. The discussion emphasizes the relationship between capacitance, charge, and voltage in the context of dielectrics. Understanding these principles is crucial for comprehending capacitor behavior in electrical circuits.
Gear300
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For a capacitor not connected to a battery, why does the voltage decrease with the insertion of a dielectric. Would it be because the net electric field between the conductors is decreased?
 
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you just answered your own question. there is also less room for particles to lose potential over.
 
username2 said:
you just answered your own question. there is also less room for particles to lose potential over.

Gear300, your answer is a lot better than this one. Yes, the dielectric decreases the electric field. What do you mean "less room"?
 
alternative method :
Q=CV
V=Q/C

insert a dielectric , keeping the charge accumulated unchanged. the greater the dielectric(coefficient e), the greater the capacitance and the lower the voltage across

but why. it is related to the properties of dielectric ... and polarization makes the V decreases as well as ... that's another story
 
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