How Does Invariance Apply in Relativity Theory?

AI Thread Summary
The discussion revolves around the application of invariance in relativity theory, specifically focusing on the transformation of angular frequency and wave vector. Participants are attempting to derive expressions for ω' and k' in terms of ω and k, while grappling with the mathematical complexities involved, particularly with dot products and vector analysis. There is a consensus that the problem is fundamentally mathematical, emphasizing the need to focus on equations rather than physical interpretations of events. A suggestion is made for the user to improve their proficiency in vector algebra to better tackle these relativity problems. Overall, the conversation highlights the importance of mathematical skills in understanding and applying concepts in relativity theory.
timetraveller123
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Homework Statement


upload_2017-11-17_11-55-37.png


Homework Equations

The Attempt at a Solution


ok so for w' i am getting since the s' is only moving in x direction
##
\omega' = \omega \gamma (1 + \beta)
##
is this correct then i am having some trouble in dealing with the dot product to derive for
##
\bf {ck'}
##
 

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It is not generally correct. Please show your work.
 
Orodruin said:
It is not generally correct. Please show your work.
i am not getting what you mean
this is what i did
##
\omega = 2 \pi f\\
\omega' = 2 \pi f'
##
say an event occurs infront of moving observer then
##
f' = f \gamma (1+ \beta)
##
 
vishnu 73 said:
say an event occurs infront of moving observer
You cannot make this assumption.
 
oh are you saying the event can occur above or below the x axis
 
ok then letting the event be anywhere on the xy plane then
let v be the relative velocity between s' and s
and ##\theta## be angle formed in s and ##\theta'## the angle formed in s'
f be the frequency in s and f' be the frequency in s'
upload_2017-11-17_16-20-45.png

then
##
f = f_0\\
f' = f_0 \frac{\sqrt{1 - \frac{v^2}{c^2}}}{1 - \beta cos \theta'}

##
is this correct?
 

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Last edited:
You are seriously overcomplicating things. All that is asked is how ##\omega'## and ##\vec k'## needs to be expressed in terms of ##\omega## and ##\vec k## for the expression ##\vec k \cdot \vec r - \omega t = \vec k' \cdot \vec r' - \omega' t'## to hold. You just need to make sure that this holds regardless of the values of ##t## and ##\vec x##.
 
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vishnu 73 said:

Homework Statement


View attachment 215123

Homework Equations

The Attempt at a Solution


ok so for w' i am getting since the s' is only moving in x direction
##
\omega' = \omega \gamma (1 + \beta)
##
is this correct then i am having some trouble in dealing with the dot product to derive for
##
\bf {ck'}
##

This looks like a maths problem to me. Does it really matter what these variables are? You're given a set of things (four-vectors etc.) with certain properties. I'm not sure you need to make any further assumptions about the things you are dealing with, other than the mathematical relationships you are given.

PS I see @Orodruin has just said much the same thing.
 
Orodruin said:
You just need to make sure that this holds regardless of the values of ttt and ⃗xx→\vec x.
thats just what i am having problems with

PeroK said:
This looks like a maths problem to me. Does it really matter what these variables are? You're given a set of things (four-vectors etc.) with certain properties. I'm not sure you need to make any further assumptions about the things you are dealing with, other than the mathematical relationships you are given.
the problem is i am not good at maths in relativity

please give me hints
 
  • #10
Write out both sides of the equation, identify terms with the same coordinate factor ##t##, ##x##, ##y##, or ##z##.
 
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  • #11
ok what does position vector mean like what is the r vector to event or to the moving obsever
 
  • #12
vishnu 73 said:
ok what does position vector mean like what is the r vector to event or to the moving obsever

Hint: this is a maths problem. You can forget "events" and "moving observers". Just focus on the equations now. The physics has been done by someone else: they are just asking you to do a bit of maths for them!
 
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  • #13
PeroK said:
Hint: this is a maths problem. You can forget "events" and "moving observers". Just focus on the equations now. The physics has been done by someone else: they are just asking you to do a bit of maths for them!
sir i understand what you are saying but i don't how to deal with the dot product how to separate the r' and k' vector when there is a dot between them thanks
 
  • #14
vishnu 73 said:
sir i understand what you are saying but i don't how to deal with the dot product how to separate the r' and k' vector when there is a dot between them thanks
I am sorry, but if you have problems with that part you are not mathematically prepared to tackle relativity. Before you can deal with relativity, you need to become more proficient in vector algebra and vector analysis.
 
  • #15
Orodruin said:
I am sorry, but if you have problems with that part you are not mathematically prepared to tackle relativity. Before you can deal with relativity, you need to become more proficient in vector algebra and vector analysis.
what level vector algebra is needed because i know the basics only
 
  • #16
@Orodruin
sir please tell what do i need to learn because i am more than happy to learn please guide me through this problem and this problem
 
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