How Does Mass Affect Velocity in an Elastic Collision?

AI Thread Summary
The discussion centers on the elastic collision between two pucks on an air-hockey table, focusing on the effects of mass and velocity. Puck A, with a mass of 0.023 kg and a velocity of +5.5 m/s, collides with puck B, which has a mass of 0.048 kg and is initially at rest. Participants are troubleshooting their calculations for momentum conservation in both the x and y directions, noting discrepancies in their equations. A key point of confusion arises regarding the correct application of initial and final velocities in the momentum equations. The conversation emphasizes the importance of correctly applying conservation laws and clarifying variable definitions in collision problems.
mayanfox
Messages
2
Reaction score
0
The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.023 kg and is moving along the x-axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.048 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing.

http://www.webassign.net/CJ/07_32.gif

(Puck A is 65 degrees north of east, puck B is 37 degrees south of east.)


I used MaVa = MaVa(cos 65) + MbVb(cos 37), which gives me
.1265 = .0097202Va + .03833Vb. Since the total momentum in the Y direction was zero, I also used
Va(sin 65) = Vb(sin 37)
Va = .6640Vb or Vb = 1.506Va.

Every time I plug in those numbers I get a wrong value! Am I missing some important concept, or am I just making an algebraic error?
 
Physics news on Phys.org
> I used MaVa = MaVa(cos 65) + MbVb(cos 37)

You Va on RHS should be different from initial Va on LHS.
 
Aah, thanks for pointing that out. I had the Va on the LHS as Vo when I did the problem, though, so it didn't change my answer.
 
> Va(sin 65) = Vb(sin 37)

Why? It should be MaVasin 65 = MbVbsin 37.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top