How Does Poiseuille's Law Calculate Blood Flow Speed in the Pulmonary Artery?

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The discussion centers on calculating the average speed of blood flow in the pulmonary artery using Poiseuille's Law, given specific parameters like the artery's radius, length, and pressure drop. The equation used is pi*r^4(p1-p2)/(8*viscosity*length), where clarity is sought on whether the pressure drop (p1-p2) should be expressed as -400 Pa or 400 Pa. It is noted that the sign of the pressure difference depends on the chosen direction of flow, affecting the flow rate's sign. Choosing the heart to lungs as positive results in a positive flow rate, while the opposite direction yields a negative flow rate. Understanding the sign convention is crucial for determining the correct average speed of blood in the pulmonary artery.
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The pulmonary artery, which connects the heart to the lungs, has an inner radius of 2.8 mm and is 8.5 cm long. If the pressure drop between the heart and lungs is 400 Pa, what is the average speed of blood in the pulmonary artery?

I am using the equation pi*r^4(p1-p2)/(8*viscosity*length)

Would the p1-p2 be -400N or 400N? I thought a speed couldn't be negative... but it says "pressure drop". Would the answer be in m/s?

I'm lost.
 
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It depends on which way you choose to be positive, and which way to be negative. If you choose from the heart to the lungs to be positive, the p1-p2 = 400 where p1 is the pressure at the heart and p2 is the pressure at the lungs. Then your flow rate would be positive. You could also choose from the lungs to the heart to be positive, and in that case p1 is the pressure at the lungs and p2 is the pressure at the heart, so p1-p2 = -400. Then your flowrate would be negative.
 
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