How Does Potential Difference Affect Potential Energy in a Lightning Bolt?

  • Thread starter Thread starter twigthemoogli
  • Start date Start date
  • Tags Tags
    Charge Magnitude
AI Thread Summary
The potential difference between a storm cloud and the ground is 2.13 × 10^8 V. A bolt carrying a charge of 5 C falls from the cloud to Earth. The change in potential energy can be calculated using the formula: potential energy (J) = potential difference (V) × charge (C). Therefore, the change in potential energy is 2.13 × 10^8 V multiplied by 5 C, resulting in a significant energy transfer. This illustrates the relationship between potential difference and potential energy in a lightning bolt.
twigthemoogli
Messages
1
Reaction score
0

Homework Statement


The potential difference between a storm
cloud and the ground is 2.13 × 10
8
V.
If a bolt carrying 5 C falls from a cloud to
Earth, what is the magnitude of the change of
potential energy of the charge?
Answer in units of J


Homework Equations


2.13*108
C=5


The Attempt at a Solution

 
Physics news on Phys.org
hint: the unit "volts" in SI units is "Joules per Coulomb"
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top