How Does Projectile Mass Affect Exit Speed in Physics?

AI Thread Summary
In the discussion about how projectile mass affects exit speed, the problem involves a toy cannon firing projectiles of different masses. The key equation used is F=ma, which relates force, mass, and acceleration. The initial assumption was that doubling the mass would halve the exit speed, but this was corrected by considering that the time in the barrel differs for each mass. The final speed can be derived using the equation v^2=2ad, indicating that acceleration and distance are crucial factors. Ultimately, the correct answer to the multiple-choice question is B) v/sqrt(2).
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[SOLVED] SAT Subject Test in Physics

Homework Statement


Assume that every projectile fired from a toy cannon experiences force F along the length of the barrel. If a projectile of mass M leaves the barrel with speed, V, at what speed will a projectile of mass 2M leave the barrel with?


Homework Equations


F=ma, a=(Vf-Vo)/t


The Attempt at a Solution


The force F, produces acceleration of V/t for mass m, so the same force should produce F=(2m)(v/t), so the velocity equals v/2?

This is a multiple choice question with choices A) v/2, B)v/sqrt(2), C)v, D)2v, E)4v

The book says the answer is B, but gives no explanation.
 
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dtl42 said:
The force F, produces acceleration of V/t for mass m, so the same force should produce F=(2m)(v/t), so the velocity equals v/2?
Careful: The time in the barrel is not the same for the two projectiles.
 
Oh, that's true, so how can I get around that?
 
dtl42 said:
Oh, that's true, so how can I get around that?
How do the accelerations compare? How does final speed (at the end of the barrel) depend on distance and acceleration?
 
The final speed is Acceleration/Distance, and we know the distance must be the same for both objects. Can we rearrange the v=a/d and substitute it into F=ma?
 
Wait, v doesn't equal a/d, I don't know what I'm thinking...
 
Oh, I found out how to do it, just use v^2=2ad and work it out.

EDIT: Sorry for the obnoxious triple post.
 
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