How Does Side Length Influence Electric Flux Through a Cube?

AI Thread Summary
The discussion centers on calculating electric flux through a cube with a point charge at its center. For Part A, the total electric flux through the cube is calculated using the formula Q/ε₀, resulting in 734.5 Nm²/C. In Part B, the flux through one face of the cube is determined to be 122.4 Nm²/C by dividing the total flux by six. Participants note that the side length of the cube does not factor into the calculations, which is an interesting aspect of the problem. The calculations are confirmed to be correct despite the initial confusion regarding the relevance of the side length.
kirby2
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A point charge 6.50 nC is at the center of a cube with sides of length 0.260 m.

PART A: What is the electric flux through the surface of the cube?

PART B: What is the electric flux through one of the six faces of the cube?

ATTEMPT:

A)
Total flux enclosed by the cube = Q / eo
6.5E-9/8.85 x 10^-12= 734.5

B)
flux through one of the six faces is
= Q / 6 eo
so 734.5/6 = 122.4

with the exception of units, are these right? i think I'm doing it wrong because i didn't use the side length in any of the calculations.
 
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hi kirvy2! :wink:
kirby2 said:
… i think I'm doing it wrong because i didn't use the side length in any of the calculations.

no, your method is fine :smile:
 
Agreed. It is one of the interesting things about the Coulombic force :) Maybe they were throwing you a red herring by giving you the length of the sides.
 
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