How Does Student B's Acceleration Affect Student A's Position?

metalmagik
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A rope of negligible mass passes over a pulley of negligible mass attached to the ceiling as shown above. One end of the rope is held by Student A of mass 70 kg, who is at rest on the floor. The opposite end of the rope is held by Student B of mass 60 kg, who is suspended at rest above the floor.

The first 2 questions asked for simple calculations, but now questions (d) and (e) ask:

(d) As Student B is accelerating at .25 m/s^2, is Student A pulled upward off the floor? Justify your answer.

Now I do not quite understand this..I guess it makes sense since the acceleration is so small, it doesn't have enough Fnet to make Student A go upwards. But (e) is as follows:

With what minimum acceleration must Student B climb up the rope to lift Student A upward off the floor?

I do not understand how to calculate this. I have the answer as 1.6 m/s^2 as per my teacher's key. If anyone could explain how to arrive at this answer please help me out! I have completed FBDs for these two Students so it would be fine to speak to me in terms of the forces. Thanks to anyone who could help me with this!
 
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Hint: What tension is produced in the rope when Student B climbs? How much tension is needed to lift Student A?
 
AH i just got it. thanks for the response, I realized ForceNET. So I took the difference of Student A's weight and the tension on Student B and got acceleration from that. Thanks.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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