How Does Tension in the String Compare to the Force on Block A?

AI Thread Summary
In a system with two blocks, A and B, connected by a massless string on a frictionless surface, the tension in the string is analyzed in relation to the force applied to block A. The force exerted by the hand on block A must be greater than the tension in the string because block A experiences a net force that results in acceleration. Since both blocks accelerate together, the tension in the string remains constant throughout. The conclusion is that the force of the hand on block A exceeds the tension in the string acting on block B. This understanding clarifies the relationship between the forces in the system.
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Homework Statement


The hand in the figure is pushing on the back of block A. Blocks A and B, with mass B > mass A, are connected by a massless string and slide on a frictionless surface.

Is the force of the string on B larger than, smaller than, or equal to the force of the hand on A?

Picture: http://img713.imageshack.us/img713/1030/physicsq.jpg

Homework Equations


The Attempt at a Solution



From my free body diagram, block B has a tension towards the right that should be less than the force applied to block A as they both move with the same acceleration.
 
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Consider the forces on block A.
 
Block A has a force to the right and tension in the opposing direction. Because of conservation of string, the tension should be the same for Block B? Since this is on a frictionless surface, nothing is opposing the force applied on A so there will be an acceleration to the right meaning tension should be less than the force?
 
I'd state it this way: The only forces on block A are the applied force and the string tension. The the blocks accelerate, so there must be a net force on A, thus the applied force must be greater than the tension. (And the tension is the same throughout a massless rope.)
 
Thank you! This thread can be closed.
 
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