How Does the De Broglie Wavelength Relate to Scattering Angles?

AI Thread Summary
The discussion centers on the relationship between the de Broglie wavelength and scattering angles, particularly in the context of AS level physics. Participants suggest that the teacher may have referenced the Compton effect, where a photon collides with an electron, causing the photon to scatter at a specific angle. The relevant formula for this scattering involves the change in wavelength and incorporates the Compton wavelength of the recoiling electron. This relationship highlights the momentum transfer during the collision and is linked to the photoelectric effect. Understanding these concepts is crucial for grasping advanced physics applications.
QueenFisher
we were having a discussion about this in physics and my teacher mentioned a relationship between the formula and some angle (don't know which!) but it's not on the syllabus any more, i was wondering does anyone know anything about this?

cheers for the help
 
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Was there by any chance some mention of the "Compton effect"? Or was it mentioned in terms of x-rays? Or perhaps electron diffraction?

The deBroglie wavelength is used in may advanced physics applications; you'd have to give us some kind of clue here.
 
well it must be something pretty simple as it's only AS level physics, it came up during a discussion about the photoelectric effect...
 
My guess is that your teacher was talking about the Compton effect in which a photon collides with an electron. such a collision demonstrates the momentum of the photon since the electron recoils with a change in momentum. The photon (an x-ray) scatters at an angle theta according to the following formula:
\lambda '- \lambda=(h/mc)(1-cos \theta)

the (h/mc) term is the "Compton wavelength" of the recoiling electron
 
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