How Does the DeBroglie Wavelength of an Electron Compare to Familiar Objects?

AI Thread Summary
The de Broglie wavelength of an electron traveling at 2*10^6 m/sec is calculated to be approximately 3.64*10^-10 meters. This wavelength is comparable to atomic dimensions, specifically around 0.364 nanometers, which is close to the size of hydrogen atoms. The discussion highlights that 1 Ångström equals 10^-10 meters, emphasizing its relevance in atomic and molecular scales. Participants express confusion about familiar structures at this scale, with some humorously referencing the term "Ångström." Understanding this wavelength is crucial for grasping quantum mechanics and atomic physics.
pdhakal
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a. Find the deBroglie wavelength of an electron traveling at 2*10^6 m/sec.
b. Does this length come close to any familiar dimensions? Explain

For part a. I did
lambda=h/(mv)
=(6.626*10^-34 J sec)/(9.11*10^-31 kg*2*10^6 m/sec)
= 3.64*10^-10 meters

I have the first one but I did not understand the second part.
Could someone please help me with this?
Thanks
 
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Do you know some structure with a size of roughly 3.64*10^(-10) meters?
10^(-10)m even has a special name due to its importance.
 
I don't have any idea about the structure roughly to taht size but I know 10^-10 is 1 Armstrong
 
And where is that unit used?
(did you really need help to get that question?)
 
pdhakal said:
I don't have any idea about the structure roughly to taht size but I know 10^-10 is 1 Armstrong

Ångström
 
Had it been Armstrong, it must have been full of drugs, so much greater than 10-10m.
 
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