How Does the Doppler Effect Alter Light's Wavelength in Space?

  • Thread starter Thread starter rocephin
  • Start date Start date
  • Tags Tags
    Light Space
rocephin
Messages
4
Reaction score
0
1. The problem statement:


My problem is regarding doppler effect for light . I have read in textbook that blue/red shift occurs in case of light when it travels from a star to Earth .

Q no 1:
Now, in case of sound it is easy to under stand that sound wave comprise of rarefaction and compression , in this way as a result of continuous compression and rarefaction , the energy of sound waves get reduced and that reduction appears as wave length shortening.

But in case of light how wave length gets reduced?
Is energy lost during motion?

Q2:
If light travels travels from point A in space to point B, does it approach point B with a frequency and wavelength different from frequency and wavelength it had while initially moving?



HELP!
 
Physics news on Phys.org
i don't think you understand the doppler effect properly

In sound the motion of the emitter respective to the receiver is what causes the Doppler effect. In the simplest terms: If something stationary emits a signal every second then the distance between the signals would be its velocity 'v' times one second. if the emitter then starts moving with velocity 'b' in the direction of the signal then the distance between each signal would be v-c times one second i.e. it's wavelength has been shortened. So it is the motion as well as the gravitational field of the stars that governs the redshift
 
Last edited:
What I am saying is that as wavelength of a sinusoidal wave is the spatial period of the wave – the distance over which the wave's shape repeats , then frequency or number of waves passing through a point should change , not wavelength.
 
hi rocephin! :smile:
rocephin said:
Now, in case of sound it is easy to under stand that sound wave comprise of rarefaction and compression , in this way as a result of continuous compression and rarefaction , the energy of sound waves get reduced and that reduction appears as wave length shortening.

the sound wave does not lose energy

the number of wave-tops passing a stationary point per second is obviously less than the number passing a point that is moving towards the wave …

ie the frequency increases (blue-shift)

and if the point is moving away, the frequency decreases (red-shift) …

(same for any wave, including light)

it's just geometry! :wink:
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top