How Does the Normal Force Compare to the Car's Weight in a Circular Valley?

Thread starter courtney1121
Start date Nov 21, 2006
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Force Normal Normal force Weight

AI Thread Summary

In a circular valley with a radius of 310 m, a car traveling at a constant speed of 23 m/s experiences a normal force that can be calculated in relation to its weight. The cross section refers to the circular shape of the valley, which affects the forces acting on the car as it moves through the curve. The centripetal force required to maintain the car's circular motion is provided by the difference between the gravitational force and the normal force. As a result, the normal force is greater than the car's weight when it is at the lowest point of the valley. Understanding these forces is crucial for analyzing the car's dynamics in circular motion.

Nov 21, 2006

courtney1121

A car travels at a constant speed of 23 m/s through a small valley whose cross section is like a circule of radius 310 m. What is the magnitude of the normal force on the car, expressed as a multiple of the car's weight?

what does it mean by the cross section and how does it relate to the problem?

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Nov 21, 2006

QuantumCrash

You can assume the valey is sort of a semi-cylinder and the car travels on the circular part of it.

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