How Does Thermal Energy Compare to Ionization Energy in a Flame?

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The discussion centers on comparing thermal energy and ionization energy in a flame, specifically regarding lithium. The thermal energy can be approximated as RT, while the first and second ionization energies for lithium are significantly higher, at 520 kJ/mol and 729 kJ/mol, respectively. Participants debate whether significant ionization of lithium occurs in the flame, with some arguing that the high ionization energy suggests minimal ionization. Clarifications are sought regarding the meaning of "ionization energy of the flame" and the relationship between thermal energy and ionization energy. Ultimately, the consensus leans towards the conclusion that lithium is not significantly ionized in the flame due to its high ionization energy relative to the thermal energy present.
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Homework Statement


The energy of particles in a flame at a temperature T might be described by a
Boltzmann distribution. Temperature can be converted to energy (and thereby velocity)
using the gas constant R = 8.3145 J mol-1 K-1. Let us approximate thermal energy in the
flame by RT (squiggly lines mean approximately) where T is in degree Kelvin:
thermal energy ≈ RT
The first ionization energy for Li is 5.20 x 10 2 kJ/mol and the second ionization energy
is 7.29 x 103 kJ/mol. Assume that your Bunsen burner reached 869 ºC, and that nearly all
of Li atoms heated in your Bunsen burner had energies less than 4 x RT. Would you or
would you not expect significant ionization in the flame? Explain.

The Attempt at a Solution


The ionization energy for Li is the opposite of the ionization energy of the flame. The second Li ionization is fairly high, and as a result, I would expect that the ionization energy of the flame is not very significant because the Li ionization is high. Lithium is high on the list of reactive elements, they increase in reactivity going down, example, francium is much more reactive than lithium, I would expect a much larger ionization of flame from franciums ionization compared to lithium.
Am I correct?
 
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physicsnobrain said:
The ionization energy for Li is the opposite of the ionization energy of the flame.
What does "ionization energy of the flame" mean?

physicsnobrain said:
Lithium is high on the list of reactive elements, they increase in reactivity going down, example, francium is much more reactive than lithium, I would expect a much larger ionization of flame from franciums ionization compared to lithium.
I don't understand what this has to do with the problem. You only have to consider lithium in the flame. Is it significantly ionized or not?
 
DrClaude said:
What does "ionization energy of the flame" mean?


I don't understand what this has to do with the problem. You only have to consider lithium in the flame. Is it significantly ionized or not?

no it is not significantly ionized. I said that.
 
physicsnobrain said:
no it is not significantly ionized. I said that.
But based on what? I would like to see some calculations...
 
DrClaude said:
But based on what? I would like to see some calculations...

well obviously R x T is wayyyyyyyyy less than 4(R)(T)

That is why
 
physicsnobrain said:
well obviously R x T is wayyyyyyyyy less than 4(R)(T)
You're comparing ##RT## with ##4RT##? I think you misunderstood the statement of the problem. First, it says that ##E_\mathrm{thermal} \approx RT##, then that ##E_\mathrm{thermal}## is at most ##4RT## (the energy follows a distribution, it is not a fixed value). So how does that compare to the ionization energy?
 
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