How Does Torque Affect a Cart Overcoming a Step?

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The discussion centers on calculating the torque experienced by a garden cart loaded with firewood as it encounters an 8 cm high step. The cart, weighing 64 kg, has its center of mass directly over the axle, and the wheel diameter is 60 cm. The user attempts to determine the torque caused by the step's height and the force applied to the wheel. There is confusion regarding whether the torque due to the step is zero or a different value. The conversation emphasizes the application of torque equations and Newton's laws in solving the problem.
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Homework Statement


A garden cart loaded with firewood is being pushed horizontally when it encounters a step 8.0 cm high, as shown in the figure. The mass of the cart and its load is 64 kg, and the cart is balanced so that its center of mass is directly over the axle. The wheel diameter is 60 cm. You are pushing the cart horizontally by a handle.


Homework Equations


torque = rFsin(angle)
Newton's laws



The Attempt at a Solution


I tried to find the torque that occurs as a result of the step applying a force on wheel. I originally thought that the force the person was applying was equal to the force that the wheel applied to the step. Thus, since the step is 8 cm high, I thought that the torque due to the step was .30(F)sin(74.5). But I am having trouble figuring out if this is equal to zero or something else?
 
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