How Does Torque Affect the Stopping Time of a Potter's Wheel?

AI Thread Summary
The discussion focuses on calculating the torque exerted by a potter on a wheel and determining the stopping time of the wheel. The torque is calculated using the formula torque equals force times radius, resulting in 0.09 Nm. To find the stopping time, the torque equation is rearranged to solve for angular acceleration, which is then used alongside the initial angular velocity to determine the time required for the wheel to stop. The moment of inertia of the wheel and bowl is given as 0.11 kg*m^2, which is essential for these calculations. Understanding these relationships is crucial for accurately determining the effects of torque on the stopping time of the potter's wheel.
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A potter is shaping a bowl on a potters wheel rotating at constant angular speed. The frictional force between her hands and the clay is 1.5N total. A. How large is her torque on the wheel, if the diameter of the bowl is 12 cm? B. How long would it take for the potters wheel to stop if the only torque acting on it is due to the potters hand? The initial angular velocity of the wheel is 1.6 rev\s, and th moment of inertia of the wheel and the bowl is 0.11kg*m^2.

So part A is just the force times the radius right? ie. 1.5N*.06m=.09Nm. Part B is my sticking point. I'm not really sure where to go from here.
 
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For Part B, you need to use the equation for torque: Torque = Moment of Inertia x Angular AccelerationYou can rearrange this equation to solve for the angular acceleration given the torque and the moment of inertia. Then, use the equation for angular velocity given angular acceleration and initial angular velocity to solve for the time it takes for the wheel to stop.
 

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