How far apart are two stars resolved by a 68-cm telescope?

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Homework Help Overview

The problem involves determining the separation distance between two stars that are 18 light-years away, using a 68-cm telescope. The resolution is limited by diffraction, and the wavelength of light is given as 540 nm.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using the formula for angular resolution based on Rayleigh's Criterion and the relationship between angular separation and physical distance. Some mention using similar triangles to relate the angle and distance.

Discussion Status

There are multiple approaches being explored, with some participants expressing uncertainty about their calculations. Guidance has been offered regarding the use of radians and the need to clarify calculation methods.

Contextual Notes

Participants note the importance of ensuring calculations align with the assumptions of small angles and the correct application of the angular resolution formula.

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Homework Statement


Two stars 18 light-years away are barely resolved by a 68 -cm (mirror diameter) telescope. How far apart are the stars? Assume \lambda = 540 <units>nm</units> and that the resolution is limited by diffraction.
Express your answer using two significant figures.



Homework Equations


Theta=(1.22 lambda)/diameter of the lense

9.4605284 × 10^15 meters


The Attempt at a Solution


I have no clue how to do this. I plugged the give info into the equation and got theta to equal 9.6882352941176470588235294117647e-7 then i just plugged this into the Pythagorean equation to get 559491313771834207552834.45286104
 
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Roughly from similair triangles:
lamba/D = separation/distance

The angle between the stars is 1.22lambda/D so you can work out this angle (remember is answer in radians) then you have the angle between two stars a distance away so getting the distance between them is easy.
Since the angles are small you can use the apprx theta = sin theta (in radians)
 
I have worked it out both ways and both of the answers i got were wrong
 
Remember, as mgb_phys stated, Rayleigh's Criterion expresses the angular distance in radians.

If you're still getting the incorrect answer I suggest you explicitly post how you're calculating the distance.
 

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