How Far Did the Robber's Car Travel in 6 Seconds with a Forgotten Brick of Gold?

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The discussion centers on calculating the distance a car travels during a bank robbery when it accelerates from rest for 6 seconds, with a brick of gold on the roof. The problem involves determining the car's acceleration using the coefficient of static friction (µs = 0.4) and applying the equations of motion. Participants suggest equating the frictional force to the force acting on the brick to find acceleration. The final calculated distance traveled by the car in this scenario is 70.56 meters. The conversation emphasizes the importance of understanding friction and motion equations in solving the problem.
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Homework Statement


During a bank robbery, one of the gangsters forgets a brick of gold on the roof of the
car. Assuming that the car accelerates from rest with a constant acceleration, and that the
brick was on the point of slipping, throughout the acceleration, how far did the car travel
in the first 6s if µs = 0.4?

(the answer is 70.56m)

The Attempt at a Solution


1. Homework Statement [/

givens:
x direction---> a=? delta x=? initial velocity=0 final velocity=?
y direction---> a=0 delta y=0 " " " = 0
mu=o.4 t=6

Homework Equations



x=(initial velocity)( time )+ 1/2 (a)(t)

The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution

 
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you have to attempt a solution first.
 
but i am not sure where to start could someone give me a hint
 
I am assuming the friction to be only between the car and the block.
say the frictional force is f=µs*m*g. but this has to be equal to the force acting on it.
so equate it to m*a and get a value for the acceleration.

Use the equations of motion where you know a, u, and t...and hence find s.
 
thanks :)
 
you'r welcome! :smile:
 
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