How Far Did the Stuntwoman Fall Based on Doppler Shift Analysis?

AI Thread Summary
The discussion revolves around calculating the distance a stuntwoman falls based on the Doppler shift of her scream. The initial frequency of her scream is 4.05 kHz, but it is heard at 3.77 kHz by the camera crew, indicating she is moving towards them. The participant successfully calculated her falling speed to be 25.5 m/s and sought guidance on determining the distance fallen. Using kinematic equations, they found that the stuntwoman would fall approximately 33.15 meters to reach that speed under gravity. The conversation highlights the application of physics principles in practical scenarios.
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Homework Statement



A stuntwoman is preparing to take a punch, crash through a "candy glass" window, and fall a long distance. The script calls for her to emit a piercing scream just before she hits the "ground." In reality, she will land on a waiting airbag. Lights! Camera! Action! The primary camera crew, filming from her starting height, hears her last-instant scream at a frequency 3.77 kHz. Her scream has a frequency of 4.05 kHz when she is at rest. How far did she fall? Report this as a positive distance.

Homework Equations



Fl=Fs(v-Vl/v+Vs)


The Attempt at a Solution



I have easily found the speed of the girl falling to be 25.5m/s but I don't even know where to start as far as finding her distance. I have considered finding the wavelength but I don't know where to go from there. Do I need to you an echo equation for this? I've been looking at it for a solid 2 hours convinced I could figure it out but I'm about to the point where I need a little guidance. I don't need an answer I just need an idea of where to go from here. This isn't due for another 3 weeks but its driving me insane.

THANKS!
 
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Good 'ol kinematics might help. :wink: You know g = 9.8 m/s2. Assuming her initial position and velocity were both approximately zero, how far would she have to fall to reach the target velocity, when accelerating at g?

[If you don't remember the single, direct equation for this, you can use a couple other kinematics equations. Use one equation to calculate the time it takes to reach the final velocity, then another equation to calculate the distance.]
 
I was afraid it would be something like that. . . thanks. I should be able to get it from here but if not ill be back within the next 20 minutes haha
 
Wow, that was ridiculously easy. 33.15m. Thanks for the help!
 
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