How Far Does a Tuning Fork Tine Travel in One Minute?

  • Thread starter Thread starter Sace Ver
  • Start date Start date
  • Tags Tags
    Sound Waves
AI Thread Summary
The discussion focuses on calculating the total distance a tuning fork tine travels in one minute, given an amplitude of 0.25 cm and a frequency of 150 Hz. The key points include understanding that the distance traveled in one period is twice the amplitude, as the tine moves back and forth. With a frequency of 150 Hz, there are 150 cycles in one second, leading to 9,000 cycles in one minute. Therefore, the total distance traveled by the tine in one minute is 4,500 cm. The conversation emphasizes the relationship between amplitude, frequency, and total distance traveled in oscillatory motion.
Sace Ver
Messages
79
Reaction score
2
Member warned to show some attempt and relevant equations.

Homework Statement



The tine of a tuning fork, when struck, has an amplitude of 0.25cm. If the frequency is 150 Hz, what total distance with the tine travel in 1.00 min?

Homework Equations

The Attempt at a Solution



Not sure how to solve this problem.
 
Physics news on Phys.org
What distance does the tine travel in one period?
How many periods in one minute?
 
PietKuip said:
What distance does the tine travel in one period?
How many periods in one minute?

PietKuip said:
What distance does the tine travel in one period?
How many periods in one minute?
Is one period one second?
 
PietKuip said:
What distance does the tine travel in one period?
How many periods in one minute?
Do I need to use formula T=1/f
 
Sace Ver said:
Is one period one second?
No. But you do not need to know the period of oscillation to say what distance the tine travels during one oscillation.
 
Sace Ver said:
Is one period one second?
Period, in this context, means the time taken for one complete cycle.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top