How Far Does the Block Travel After Being Struck by the Bullet?

  • Thread starter Thread starter pkhor
  • Start date Start date
AI Thread Summary
To determine how far the block travels after being struck by the bullet, the initial momentum of the bullet and block must be calculated, leading to a final velocity of approximately 0.9975 m/s for the combined mass after the collision. The projectile motion concept is essential for finding the distance the block travels horizontally before hitting the ground. First, calculate the time it takes for the block to fall 1.2 m using the formula t = sqrt(2h/g), where h is the height and g is the acceleration due to gravity. Then, use the horizontal velocity and time to find the horizontal distance traveled. This approach will yield the distance from the table to where the block hits the floor.
pkhor
Messages
3
Reaction score
0
the original problem:
A 0.010-kg bullet traveling horizontally at 400.0 m/s strikes a 4.0-kg block of wood sitting at the edge of a table. The bullet is lodged into the wood. If the table height is 1.2 m, how far from the table does the block hit the floor?

this is what i did:

lets the mass of bullet = m2
the mass of block of wood = m1
velocity of the block of wood before the collision take place = v1
velocity of the bullet = v2
velocity of the block and bullet after the collision take place = vf
momenta of the block = p1
momenta of the bullet = p2

the momentum of block and bullet after collision equals the sum of momenta of the block and the bullet before the collision:

pf = pi

The initial momentum is the sum of the momenta of the block and bullet

pf = p1 + p2

Since the block is initially at rest, p1 = 0. Then

pf = p2
or
(m1 + m2)(vf) = (m2)(v2)

Solving for vf:

vf = [(0.010)(400.0)]/(4.0+0.010) = 0.9975 m/s

And I stuck here because I didn't know how to calculate the distance from the table to the point that the block hit the floor.
Am I have to use the projectile motion concept?
Your help would be highly appreciate.
 
Physics news on Phys.org
Yes, you have to use the projectile motion formulas.
 


Yes, you will need to use the concept of projectile motion to calculate the distance from the table to the point where the block hits the floor. Here are the steps you can follow:

1. First, you need to determine the initial velocity of the block, v1. Since the block is initially at rest, its initial velocity will be 0 m/s.

2. Next, you can use the equation of projectile motion to calculate the time taken for the block to hit the floor. The equation is t = 2v1/g, where v1 is the initial velocity of the block and g is the acceleration due to gravity (9.8 m/s^2).

3. Once you have the time, you can use the equation s = ut + 1/2at^2 to calculate the distance traveled by the block before hitting the floor. Here, u is the initial velocity, t is the time, and a is the acceleration due to gravity.

4. Finally, you will have the distance from the table to the point where the block hits the floor. You can subtract this distance from the height of the table (1.2 m) to get the final answer.

I hope this helps! Let me know if you have any other questions. Good luck!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top