How Far Does the Car Travel to Overtake the Truck?

AI Thread Summary
A car accelerates at 2.80 m/s² from a stop at a traffic light, while a truck moves at a constant speed of 17.0 m/s. The problem is to determine how far the car travels to overtake the truck after it starts moving. The car's position can be calculated using the equation X = 1/2*a*t², while the truck's position is defined by its constant velocity. The key to solving the problem lies in finding the time and distance at which both vehicles have the same position, indicating the car has overtaken the truck.
The1
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Homework Statement


At the instant the traffic light turns green, a car that has been waiting at an intersection starts ahead with a constant acceleration of 2.80 m/s^2. At the same instant a truck, traveling with a constant speed of 17.0 m/s, overtakes and passes the car.

How far beyond its starting point does the car overtake the truck?

Homework Equations


One of the four constant acceleration equations


The Attempt at a Solution


I honestly have no idea how to start this, but I think I need a graph to solve.
 
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You do not need a graph to solve this problem, but a picture always helps.

In order to get help on this forum you need to show some work.

Can you list the variables you know and don't know?
Can you give me the equations of motion for one or both of the vehicles?

Give me something so I can know what is confusing you.
 
Well, I'm a bit lost on this question but here goes.

Car:
I think I use the equation X = 1/2*a*t^{2} because X initial and V initial are 0.Of course I don't know how helpful this is as I don't have the time.

Truck:
All I know is the constant velocity is 17 m/s. The truck overtakes the car at X=0

The intersection is X=0 and t=0.

I need to know the distance it takes the car to overpass the truck, and at what velocity.

Again, I'm not to sure of the accuracy of this post
 
your post is accurate,
now, what is the equation of the coordinate X1 of the truck in fuction of time ?

now the truck intersects the car at t=0 X=0, that's true, but we need the second intersection time and distance.

let X(t) the coordinate of the car, let X1(t) the coordinate of the trucks,
what's the relation between X(t) and X1(t) when the car and truck intersect again ?
 
The1 said:
Well, I'm a bit lost on this question but here goes.

Car:
I think I use the equation X = 1/2*a*t^{2} because X initial and V initial are 0.Of course I don't know how helpful this is as I don't have the time.

Truck:
All I know is the constant velocity is 17 m/s. The truck overtakes the car at X=0

The intersection is X=0 and t=0.

I need to know the distance it takes the car to overpass the truck, and at what velocity.

Again, I'm not to sure of the accuracy of this post

As tabchouri said, this sounds good. Now, what do we know about the x coordinates of both vehicles when they intersect?
 
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