How far does the police car travel to catch a speeder traveling at 180 km/hr?

  • Thread starter Thread starter Neal Parikh
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    Car Kinematics
AI Thread Summary
To determine how far the police car travels to catch a speeder going 180 km/hr (50 m/s), the relevant equations of motion must be applied. The police car starts from rest and accelerates at 3.7 m/s², while the speeder maintains a constant speed. The initial position (xo) of the police car is 0, and its initial velocity (v0) is also 0. The conversion of the speeder's speed to meters per second is necessary for consistent unit usage. The discussion emphasizes the importance of correctly applying kinematic equations to solve the problem.
Neal Parikh
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Homework Statement


A police car at rest, is passed by a speeder traveling at constant speed of 180 km/hr, take off in hot pursuit accelerating at 3.7 m/s². How far has the police car traveled to catch the speeder?

Homework Equations


I think we would use x = xo + vot + 1/2at^2[/B]

(Or maybe V^2 = vo^2 + 2a(x-xo)?I am getting confused with which equations are relevant).

The Attempt at a Solution


I know xo is 0 because it is the start position at rest, vot is also 0 because its not moving. I am confused as to what I do with the 180 km/hr (I converted to 50 m/s)
 
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Definitely want to convert to m/s so that all the units are the same. I would also write out what you know about each car. Treat them as separate questions.
 
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