How Far Is the Sound Level from a Loudspeaker at Different Decibels?

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The discussion focuses on calculating the distance from a loudspeaker where sound levels reach 120 dB (threshold of pain) and 60 dB, given a loudspeaker's power and efficiency. The speaker uses 65W of electrical power with a 0.75% efficiency, resulting in an acoustical power of 0.4875W. The user calculated distances of 0.197m for 120 dB and 197m for 60 dB, questioning the relevance of frequency in these calculations. Responses confirm that frequency does not need to be included, as no phase information is provided. The calculations appear correct based on the provided formulas.
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Homework Statement


A loudspeaker uses 65W of electrical power at 1kHz and converts this electrical power into acoustical power with an efficiency of 0.75%. Determine the distance at which the sound level is a) at the threshold of pain (120db) and b) 60db. Assume the loudspeaker emits sound waves uniformly in all directions.


Homework Equations


beta = 10log(I/Io)
I = P/4pir^2


The Attempt at a Solution


I know how to solve this usually, but what is throwing me off is the inclusion of the frequency of the electrical power.
In the second equation, I used a power of 0.0075(65)=0.4875W. And did the calculations. I obtained 0.197m for a) and 197m for b).

Is this right, or do I need to include the frequency somehow?
 
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Good question. I don't think that the frequency comes into it because I don't see any sort phase information, which I think you would need if there was some kind of frequency dependence. So yeah, I think you are right in just using the amplitude.
 
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