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A 4.0 kg bundle starts up a 30° incline with 128 J of kinetic energy. How far will it slide up the plane if the coefficient of friction is 0.30?So, I began finding the Normal
N=W(y)=4cos30=3.46
Then found friction
f=uN
f=.3*3.46=1.04
So
E=E
K=Ug + Q
K=mgh + fd
K=mg(dsin30)+fd
128=4(9.8)(.5)d+(1.04)d
128=20.64d
d=6.2m
But the answer says 4.3m. What's wrong?
Thanks!
EDIT:
So I figured it out... N=4*9.8cos30. Duh.
N=W(y)=4cos30=3.46
Then found friction
f=uN
f=.3*3.46=1.04
So
E=E
K=Ug + Q
K=mgh + fd
K=mg(dsin30)+fd
128=4(9.8)(.5)d+(1.04)d
128=20.64d
d=6.2m
But the answer says 4.3m. What's wrong?
Thanks!
EDIT:
So I figured it out... N=4*9.8cos30. Duh.
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