- #1
subopolois
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Homework Statement
How far will a box slide if its initial velocity is 1.5 m/s, kinetic friction is 0.15 and the object is 30 kg
Homework Equations
a= (kinetic friction)(acceleration due to gravity) and
V(final)^2 - V(initial)^2 = 2(a)(D)
The Attempt at a Solution
a= 0.15 x 9.81 m/s^2
= -1.47 m/s^2 (negative since it is slowing down)
D= V(final)^2 - V(initial)^2 / 2a
= 0 - (1.5 m/s)^2 / 2(-1.47 m/s^2)
= -2.25 m/s^2 / -2.94 m/s^2
= 0.76 m
did i do everything right? seems to me like it should go a little further given the value of friction...