How Far Will the Ice Cube Travel Up the Slope After Release?

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An ice cube weighing 62.0 g is released from a compressed spring on a 27.0° slope, and the spring constant is 27.0 N/m. The user initially calculated the distance traveled up the slope as 118 cm but found this to be incorrect. They used the final velocity from the spring to analyze the motion and applied gravitational acceleration along the slope. Ultimately, the user resolved the issue independently and expressed frustration with the Mastering Physics platform.
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Help on a problem, TIME SENSITIVE!

A 62.0 g ice cube can slide without friction up and down a 27.0^\circ slope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 11.0 cm. The spring constant is 27.0 N/m.

When the ice cube is released, what distance will it travel up the slope before reversing direction?

I tried this:

I found the v_f that the spring gives the cube. I used that as v_i for the part of motion not acted on by the spring. for accel. I used a = -g*sin(theta). I used v_f = 0. Solved for x. I got 118 cm. That is wrong.

Does anyone have a method that will give me the right answer? Or any advice?
 
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never mind, i figured it out.

bastards at mastering physics.
 
That site was hell. :(
 

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