How Far Will the Ice Cube Travel Up the Slope?

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A 55g ice cube compressed against a spring on a 25° slope is released after compressing the spring by 10cm, with a spring constant of 25N/m. The potential energy in the spring is converted to gravitational potential energy as the cube travels up the slope. The calculations show that the maximum height reached is 0.23m, but the user initially misinterprets the question by calculating height instead of the distance along the slope. After correcting for the slope angle, the distance traveled up the slope is determined to be 40cm. The discussion emphasizes the importance of accurately interpreting physics problems.
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Question statement
A 55g ice cube can slide without friction up and down a 25∘slope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 10cm . The spring constant is 25N/m. When the ice cube is released, what distance will it travel up the slope before reversing direction?

Relevant equations
PE_s = PE_g
PE_s = 1/2kx^2
PE_g = mgh

Attempt at a solution
Maximum height is when all energy is converted to gravitational potential energy (frictionless environment)

Thus,

PE_s = PE_g

1/2kx^2 = mgh

1/2(25N/m)(0.1m)^2 = (0.055kg)(9.8m/s^2)(h)

h = 0.23m or 23 cm
(Answer is asked for in cm)

Not sure what I am doing wrong here...
 
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You computing the height, not the distance along the slope.
 
I'm so silly. I need to learn to read questions further before answering something different.

Distance up slope would be
0.23(sin 35°) = 0.40m = 40cm

but that's not right!

How do I compute the distance up the slope?
 
Wasn't it a 25º slope?
 
Yes, it was... Thanks...

:nb)
 
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