How Fast Does a Block Travel on a Frictionless Surface After 3.7 Seconds?

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A 3.70 kg block on a frictionless surface is pulled by a force of 13.0 N at a 25.0° angle. To determine the speed of the block after 3.7 seconds, one must first calculate the acceleration using Newton's second law, focusing on the horizontal component of the applied force. The vertical component does not lift the block, so it does not affect horizontal motion. After finding the acceleration, the final velocity can be calculated using kinematic equations. Understanding the relationship between force, mass, and acceleration is key to solving the problem.
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Block on frictionless floor!

A 3.70 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=13.0 N at an angle q= 25.0° above the horizontal, as shown.





What is the speed of the block 3.70 seconds after it starts moving?

I have drawn a picture but have no idea what equation to start with. know you solve for aceeleration, then once you have accel. you just solve for Vfinal
 
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This involves force, mass and a change in speed. What principle of law relates these physcial concepts?
 


Newtons 2nd law
 


so what now? i know the equations but don't konw how to get acceleration cuase of the theta stuff
 


Assuming the vertical component is not sufficient to lift the block off the floor, use the 2nd law with the horizontal component of the applied force.
 

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