How Fast Does a Bowling Ball Travel When It Falls Off a Table?

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To determine the velocity of a bowling ball as it falls off a 1.0 m high table, the horizontal velocity is given as 10 m/s, while the vertical velocity must be calculated using the acceleration due to gravity at 9.8 m/s². The time taken to fall can be calculated using the formula for free fall, resulting in a vertical velocity of approximately 4.43 m/s upon reaching the floor. The overall velocity can then be found by combining the horizontal and vertical components using the Pythagorean theorem, yielding a magnitude of about 11.18 m/s. The direction of the velocity can be determined using the arctangent of the vertical to horizontal velocity ratio.
Michael17
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Bowling ball and table!

Can anyone please help me figure this one out;

A bowling ball of mass 7.5kg traveling at 10m/s rolls off a horizontal table 1.0 m high. Calculate the velocity of the ball as it reaches the floor, ignoring air resistance and having an acceleration due to gravity of 9.8m/s.
 
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Michael17 said:
Can anyone please help me figure this one out;

A bowling ball of mass 7.5kg traveling at 10m/s rolls off a horizontal table 1.0 m high. Calculate the velocity of the ball as it reaches the floor, ignoring air resistance and having an acceleration due to gravity of 9.8m/s.
They gave you the horizontal component of velocity. They want you to find the vertical component and then combine the 2 like Pythagoras would to yield the answer for the magnitude of the |velocity| vector. Now they may also want you to give the direction. (That would be tan-1 of the ratio of the 2.)
 

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