How Fast is an Airplane Moving at Takeoff with Constant Acceleration?

  • Thread starter Thread starter WRXSIG
  • Start date Start date
  • Tags Tags
    Airplane
AI Thread Summary
An airplane travels 277 meters down the runway and takes off in 8 seconds, prompting a calculation of its takeoff speed. The initial calculation of 34.6 m/s represents average velocity, not the final velocity at takeoff. To determine the takeoff speed, one must first calculate the constant acceleration using the equation x(t) = 1/2 a t^2. The final velocity can then be found using v(t) = a*t, with the understanding that average velocity equals half the final velocity under constant acceleration. Accurate calculations are essential for determining the actual speed at takeoff.
WRXSIG
Messages
1
Reaction score
0
airplane down the runway...

An airplane travels 277m down the runway before taking off.
Assuming that it has constant acceleration, if it starts from rest and becomes airborne in 8.00 seconds, how fast m/s is it moving at takeoff?

am i missing something here? 277/8seconds =34.6m/s?
 
Physics news on Phys.org
yes, I'm afraid you are. What you have calculated is it's average velocity, the total displacement divided by the total time. To find the velocity at take off, you first have to find what that constant acceleration is, then see how fast it's going after 8 seconds of accelerating at that rate.

you need these two equations:

x(t) = 1/2 a t^2 (assuming it starts from rest at the origin)

and

v(t) = a*t (assuming it starts from rest)
 
It's easier than that, with constant acceleration, average velocity is 1/2 the final velocity.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top