How Fast is Spaceship A Traveling Relative to Spaceship B?

AI Thread Summary
The discussion revolves around calculating the relative speed of Spaceship A, traveling at 0.500c, as observed from Spaceship B, which is moving at 0.800c. The initial approach used a velocity transformation formula, but a mistake was identified in the calculation, specifically regarding the inclusion of a square root. The correct transformation leads to the conclusion that Spaceship A is perceived to be traveling at -0.500c relative to Spaceship B. This highlights the importance of careful attention to detail in physics calculations. The issue was resolved with assistance from other forum members.
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I am doing an extra problem from my textbook as review and I am stumped.

An Earth based observer sees to spaceships approaching Earth in the same direction. Spaceship A is traveling at 0.500c and Spaceship B is traveling at 0.800c. How fast is spaceship A traveleing as viewed by an observer on spaceship B?

I used a velocity transformation like:

(0.500c - 0.800c)/sqrt(1-[(0.5c)(0.8c)/(c^2)])

The book gets -0.500c.

I am finding it difficult to see that the Earth based observer and the spaceship moving at 0.800c observe that spaceship going the same speed.

Thanks for your help.
 
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Wow! It's always the simplest of mistakes. Thanks a lot.
 
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