How Fast Must Muons Travel to Reach a Distant Target Without Decaying?

AI Thread Summary
Muons, which have a mean lifetime of 2.2 microseconds, can travel significant distances before decaying due to time dilation and length contraction at high speeds. The discussion involves calculating the N(t)/N0 ratio for muons traveling at various speeds (0.6c, 0.8c, 0.9999c) and deriving the N(L)/N0 function for muons at 0.8c. For an experiment targeting a location 50 km away, the minimum speed required for at least half of the muons to reach the target without decaying is calculated to be approximately 299,987,443.2 m/s. The calculations appear correct, and it is suggested to express the final speed in terms of the speed of light, c. The participant expresses uncertainty about the relativity concepts and seeks further assistance on related questions.
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Homework Statement


Unstable particles cannot live very long. Their mean life time t is defined by N(t) = N0e−t/τ , i.e., after a time of t, the number of particles left is N0/e. (For muons, τ=2.2µs.) Due to time dilation and length contraction, unstable particles can still travel far if their speeds are high enough

Problem 4
a) For musons at rest, traveling at 0.6c, 0.8c, 0.9999c, plot the N(t)/N0 ratio as a function of time.

b) For muons traveling at 0.8c, derive N(L)/N0 as a function of L, where L is the distance travelled, measured in the Earth RF. You don’t need to plot these functions.

c) Assume you are designing an experiment using muons beams that are directed at a target in a neighboring city 50km away. You want to have at least half of the muons reach the target without decaying. What is the minimum speed of the muons you must have?

Homework Equations


N(t) = N0e−t/τ

t_e = t_m *γ

L_m = L_e/γ

t_e & L_e is the time and length measured in the Earth frame of reference

and t_m and L_m is the time and length measured in the muon's frame of reference

I did all the parts but I feel pretty unsure about it. I was hoping you guys could take a look and let me know if it seems ok. Thanks in advance!

The Attempt at a Solution


Parts a.) and b.) are in the attached image

c.) N(L_e) = N_0 * e^(-L_e/v*τ_e)

after some algebra I end up with the expression

v = [ (τ_m*ln(2)/L_e)^2 + 1/c^2]^-1/2

τ_m = 2.2 * 10^-6 s
L_e = 50*10^3 m

after plugging in these values I get

v = 299,987,443.2 m/s
 

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Your work looks correct to me. You could express the answer for part (c) in terms of the speed of light c.
 
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