How go u find the force of gravity?

AI Thread Summary
The discussion centers on calculating the force of gravity on an object using the gravitational constant and the mass of the Earth. Participants identify errors in the initial calculation, particularly regarding the radius of the Earth, which should be in meters, and the mass of the object, which must be consistent in units. The correct formula for gravitational force is emphasized, and the importance of using appropriate units is highlighted. The final calculations suggest that the force acting on a 15 kg object should approximate 147 N, aligning with the expected gravitational acceleration of 9.81 m/s². Accurate unit conversion and consistent mass measurements are crucial for obtaining correct results.
SimpleHarmonicMotion
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I can't seem to get a correct # for the force of gravity on earth. I tried this:

6.673e-11(UGC) * 5.9742e24(mass of earth) * 15(mass of object) / 6378.1(radius of earth)^2

For some reason it gives me -.02867... and i no that can't be correct, what did i do wrong><?
 
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Radius of the earth
 
And do you want the force exerted on the object or the gravitational field strength (g)? From your working above your calculating the force exerted on an object of 15kg mass, not acceleration due to gravity (9.81 ms^{-2}).
 
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How did you get a negative number? None of the numbers in your expression are negative, so there is no possible way to get a negative answer.. What exactly are you trying to find?
 
huh? I'm confused, how do i find the force of gravity? and what's the radius of the earth?
 
The radius of the Earth is wrong you've quoted it in km it should be in metres, the gravitation constant should be negative.
 
Hootenanny said:
The radius of the Earth is wrong you've quoted it in km it should be in metres, the gravitation constant should be negative.

No it shouldn't it's positive 6.67x10-11.
 
Im sorry, I mean there should be a negative sign infront of the equation, the eqaution is usually quoted as:
F = - \frac{GMm}{r^2}
 
Hootenanny said:
Im sorry, I mean there should be a negative sign infront of the equation, the eqaution is usually quoted as:
F = - \frac{GMm}{r^2}

Hmm... Ok I've never seen it like that, I've never seen it with the negative sign there, but I guess it really doesn't matter as long as you deal with the directions correctly in the problem.
 
  • #10
That's how I've always used it, but yeah it's irrelevant as long as you define your cordinate system.
 
  • #11
well, I'm getting 2.86758e-8 but does that make sense? Is this measuring in m/s or N?
 
  • #12
SimpleHarmonicMotion said:
well, I'm getting 2.86758e-8 but does that make sense? Is this measuring in m/s or N?

Well since you're looking for the force of gravity, what do you think the units should be? And you're number is way off, if you're trying to figure out the force on a 15 kg object on the surface of the Earth using the law of gravitation it should be pretty close to 15*9.8
 
  • #13
well, since I'm way off could u point me in the right direction and tell me what i did wrong? Also, should the units be Newtons since that is the force being applied to the object?
 
  • #14
Looks to me as though you can't use a calculator. the only thing that was wrong with your initial working out is the distance should be in metres not km, other than that, putting numbers into your equation is your only other problem.:smile:

Its a force, what are the units of force? Do you define a force in terms of ms^{-2}? What exactly do you think ms^{-2} means, what do the letters actually represent?
 
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  • #15
6.673e-11 * 2.9742e24 * 15
--------------------------- =
6378000.1^2

6.673e-11 * 2.9742e24 * 15
--------------------------- =
4.0679e13

5.9799e13
--------------------------- =
4.0679e13

1.47 N

Is that correct? And btw, mass of Earth is in kg, so does it matter if i put the mass of the object in kg?
 
  • #16
You can check you answer using F = ma. You know that the acceleration due to gravity at the Earth's surface is roughly 9.8 m\cdot s^{-2}, you also know the mass of the object (15kg) and you've calculated a force so;
F = ma \Rightarrow a = \frac{F}{m} = \frac{1.47}{15} = 0.098
Which means your a factor of 10^2 out. Check you units, you logic is fine. Yes, mass units must be consistant throughout. If the object is 15g, not 15kg, this would explain yourproblem.
 
  • #17
Gravitational acceleration acting on a body at the earth`s surface: (6.67e-11*5.974e24 kg)/(6.4e6)^2 m= 9.73 m/s^2

9.73 m/ss*15 kg=145,95 N

I got an lower answer then 9,81 m/s, but I think it is because of some wrong values.
 
  • #18
SimpleHarmonicMotion said:
6.673e-11 * 2.9742e24 * 15
--------------------------- =
6378000.1^2

6.673e-11 * 2.9742e24 * 15
--------------------------- =
4.0679e13

5.9799e13
--------------------------- =
4.0679e13

1.47 N

Is that correct? And btw, mass of Earth is in kg, so does it matter if i put the mass of the object in kg?

If you are using MKS units, then the mass of both the Earth and object will be in kg.

1 km = 1000m. Check your radius. I get 147 N for my answer.

-Dan
 
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