How High Above Earth is Gravity 10% of Sea Level?

AI Thread Summary
To determine the height above Earth's surface where gravity is 10% of sea level, the gravitational force equation F = Gm1m2/r² is utilized. The acceleration due to gravity at sea level is expressed as F/m = GM/r², where r is the Earth's radius. To find the height where gravity is reduced to 10%, the equation must be adjusted to account for the new distance from the Earth's center, leading to the expression GM/(r+x)². By solving for x, the distance from the Earth's surface can be calculated. Further assistance is available if needed for solving the equation.
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Homework Statement


At what height above the Earth's surface is the acceleration due to gravity 10% of that at sea level?

Homework Equations


F= Gm1m2/r(squared)


The Attempt at a Solution


I think some how one of the masses is moved over so that F/m=a and I think .10 is multiplied times something like (r squared) or (r + x)squared.
 
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As you said, F/m=a. When at the surface of the Earth at sea level:

\frac{F}{m}=\frac{GMm}{m(r+x)^2}=\frac{GM}{x^2}

where x= radius of Earth, and since at the sea level r would be zero.

Now what is 10% of this? After you find this, can you set up an equation and solve for the distance from Earth? If you need more help feel free to ask. Good Luck!
 
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