How High Does a Cannonball Go When Fired Straight Up at 28m/s?

AI Thread Summary
A cannonball fired straight up at a velocity of 28 m/s will reach a maximum height determined by the conservation of energy principle, specifically using the equation mgh = 1/2 mv^2. The mass of the cannonball is irrelevant in this calculation, as it cancels out when solving for height. By substituting any mass value, such as 1 kg or 2 kg, the same maximum height will be obtained. The key takeaway is to focus on the energy conservation equation to find the maximum height. Thus, the setup is correct, and the mass can be disregarded in the calculations.
mayhemlikeme
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Homework Statement


a cannon is fired out of a cannon at a velocity of 28m/s and at an angle of 90°. Straight up. Assume it starts at a height of 0, figure out the max height it will reach. Air resistance is ignored.

Homework Equations




The Attempt at a Solution


I'm not 100% on this but I think with conservation you can use the equation: mgh= 1/2mv^2
I just need help setting it up I'm usually pretty good working it out. Thanks in advance.
 
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mayhemlikeme said:

Homework Statement


a cannon is fired out of a cannon at a velocity of 28m/s and at an angle of 90°. Straight up. Assume it starts at a height of 0, figure out the max height it will reach. Air resistance is ignored.

Homework Equations




The Attempt at a Solution


I'm not 100% on this but I think with conservation you can use the equation: mgh= 1/2mv^2
I just need help setting it up I'm usually pretty good working it out. Thanks in advance.

You've already set it up correctly. Cancel the m and solve for h.
 
Dick said:
You've already set it up correctly. Cancel the m and solve for h.

How do you set it up without knowing mass?
 
mayhemlikeme said:
How do you set it up without knowing mass?

Put the mass equal to 1kg. Solve it. Put the mass equal to 2kg. Solve it. You'll get the same answer. The mass doesn't matter. It cancels.
 

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