How High Is the Diving Platform?

AI Thread Summary
The discussion revolves around calculating the height of a diving platform based on a jump with a horizontal velocity of 1.81 m/s and a fall time of 1.4 seconds. The correct kinematic equation for vertical motion is identified as y = vi*t - 0.5gt^2, with gravity set at 9.8 m/s². After some back-and-forth, it is clarified that the initial vertical velocity is zero, leading to the conclusion that the platform is approximately 9.604 meters high. The participant expresses relief upon confirming the solution and seeks further assistance with another problem. The conversation highlights the importance of understanding kinematic equations in solving physics problems.
Londoncalling
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Homework Statement



You jump off a diving board with a horizontal velocity of 1.81 and land in the water 1.4 seconds later. Gravity=9.8. How high is this platform?

Homework Equations


x=2.534, if that helps.


The Attempt at a Solution


I got 7.07 but this is not right...
 
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Hi Londoncalling, welcome to PF.
What is the velocity in the vertical direction? What is the kinematic equation, which relates the initial velocity, time , acceleration and displacement?
 
y=vit-.5gt2 right?
I'm not sure though, we haven't learned it yet.
 
In the vertical direction the initial velocity is ...?
Your equation is right. But put -y for the displacement because it is also in the downward direction like g.
 
Okay so -y=vi -.5*9.8*1.42.
Then -y=vi*1.4-(4.9*1.96)
-y=vi*1.4-(9.604)
But there are 2 variables and only one equation... I thought you couldn't do that...?
 
Or is your horizontal v of 1.81 the initial velocity?
 
The vertical velocity is zero.
 
So it's 9.604 m high then?
Edit: Yes, I got it right! Thank you SO much, you have no idea how relieved I am. Would you be able to help me with another problem (it's in a different post)...?
 
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