How High is the Sea Cliff Based on Sound Travel Time?

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To determine the height of the sea cliff based on the sound travel time, the problem involves calculating the time taken for a rock to fall and the time for the sound to travel back up. The equations used are h = 1/2 * g * t1^2 for the rock's fall and t2 = h/340 for the sound's ascent. The total time for both events is 4 seconds, leading to the equation t1 + t2 = 4. By expressing t1 and t2 in terms of h and substituting into the total time equation, the height of the cliff can be solved.
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Please help! I've been both conceptually blocked for quite some time and need help fast!
A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 4.0 later. Given the speed of sound is 340m/s, calculate how high the cliff is in meters.
 
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If h is the height of the cliff, time taken by the rock to fall is given by

h = 1/2*g*t1^2.

Time taken by the sound to reach the top of the cliff is t2 = h/340.

Now t1 + t2 = 4 s.

Substitute the values of t1 and t2 in the above equations and solve for h.
 
rl.bhat said:
If h is the height of the cliff, time taken by the rock to fall is given by

h = 1/2*g*t1^2.

Time taken by the sound to reach the top of the cliff is t2 = h/340.

Now t1 + t2 = 4 s.

Substitute the values of t1 and t2 in the above equations and solve for h.





So do you mean solve to T1 in the first equation, then add the two together and solve for h?
 
Get t1 in terms of h. Then get t2 in terms of h.
& Substitute these into t1 + t2 = 4.
 
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