How Is Doppler Frequency Calculated for a Mobile Receiver?

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    Doppler Frequency
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To calculate the Doppler frequency for a mobile receiver at 900MHz moving at 100 km/hr, the relevant formula involves the speed of sound and the speed of the mobile source. The direction of motion affects whether the frequency is redshifted or blueshifted, which is crucial for applying the correct formula. A suggested formula is f1 = f(C1/(C1 + Vs)), where C1 is the speed of sound (343 m/s), f is the original frequency, and Vs is the speed of the mobile phone. The discussion emphasizes the importance of determining the motion's direction to correctly assess the frequency shift. Understanding these concepts is essential for solving related problems effectively.
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Homework Statement


For a mobile receiver operating at a frequency of 900MHz and moving at 100Km/hr.


Homework Equations


Find Doppler frequency.


The Attempt at a Solution

 
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Welcome to PF!

Hi jerin_007! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Its just a single formula.. I need to know that.
 
ok …

then what equations has your professor given you on the subject (or what equations does your book give you)?

and which of those equations do you think will work in this case?
 
If that so.. i could have found it.. All i know is how to find doppler spread.. But doppler frequency i can't think of and it isn't there in the book.
 
You obviously have access to a computer with an internet connection. Search for Doppler shift or Doppler effect, and see what you find.
 
This looks like a simple doppler shift problem:

you should state which direction of motion the moblie phone is in, this determines whether the the phone is redshifting or blueshifting, so that we know what formulas to use.

i'm going to guess you're dropping the mobile phone down something, which means redshifting.

Which should be (correct me if I'm wrong): f1 = f(C1/(C1+Vs))

Where C1 = Speed of sound (343 ms-1)
f = is the original frequency (900hz)
Vs = the speed of the source (mobile phone 100km/hr)
f1 = new frequency

The phone is redshifting therefore the frequency will be less, i'll let you work the rest out.

quite interesting too, i have an exam question similar to this that is very soon.
 
Thanks phycud...
 

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