How Is Impulse Calculated in a Two-Dimensional Collision?

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To calculate impulse in a two-dimensional collision, first determine the components of the ball's velocity using trigonometric functions based on the angle of impact. The impulse can be calculated using the formula F dt = m*v, where m is the mass of the ball and v is the change in velocity. Since the ball rebounds with the same speed and angle, the change in velocity must be considered in both the x and y directions. The average force exerted by the ball on the wall can be found by dividing the impulse by the contact time of 39.0 ms. Understanding the vector components is crucial for accurately calculating the impulse and average force in this scenario.
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A ball of mass 7.0 g with a speed of 25.2 m/s strikes a wall at an angle 23.0 ° and then rebounds with the same speed and angle. It is in contact with the wall for 39.0 ms. What is the magnitude of the impulse associated with the collision force?
What is the average force exerted by the ball on the wall?

The only equation I know for impulse is:
F dt=m*v

I'm not sure how to treat this problem since it has an angle, and impulse isnew.
 
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try drawin a picture : then set some coordinates and then use trigonometric functions to see what's the speed in the axis that's in the right angle towards your wall (sounds confusing?) and then just apply it to the equation you have
 
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