How is Kinetic Energy Conserved in an Elastic Collision?

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Homework Statement


A 8.5 kg steel ball, traveling left to right at 12 m/s, undergoes an elastic collision with a 5 kg steel ball at rest. To the nearest Joule, what is the Total Kinetic Energy of the two balls after collision? If the first ball has a mass of 10 kg and the second ball is traveling at it with a speed of 3 m/s, what is the velocity, to one decimal place, of the first ball after collision? What is the velocity of the second ball to one decimal place?

Homework Equations



1/2mvi2+1/2mvii2=KE

The Attempt at a Solution


Question 1:
1/2 (8.5)(122)= 612 J
Question 2 & 3:
I'm not sure the equation needed to solve for the needed. I'm pretty sure that if I can get question 2 then the same method will be used to solve question 3.
 
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For questions 2 and 3 you need to conserve momentum in addition to energy conservation.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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