How Is the Retarding Torque Calculated in a Rotating System with Friction?

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The discussion focuses on calculating the retarding torque in a rotating system with friction, specifically involving a steel rod with attached masses. The initial angular velocity is converted from 30 revolutions per second to 188.4 rad/s, and the angular acceleration is calculated as -5.89 rad/s², indicating a deceleration due to friction. The user seeks clarification on using the moment of inertia formula, realizing that the total moment of inertia must include contributions from both the rod and the attached balls. There is confusion about whether friction is the sole torque causing the deceleration. The conversation emphasizes the importance of accurately calculating the moment of inertia to determine the retarding torque.
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1. "A small ball of mass 1.06 is attached to each end of a thin steel rod of length 1.2 m and mass 6.4kg. The rod is constrained to rotate in the horizontal plane about a vertical axis through its midpoint. At some instant, it is observed to rotate with an angular velocity of 30 rev / s. Due to friction, it comes to rest 32 seconds later. Assuming a constant frictional torque, compute

the retarding torque exerted by friction.



2.

First I converted the initial angular velocity to rad/s which is 188.4 rad/s

I computed the angular acceleration to be -5.89 rad/s2

we know the final angular velocity is 0

I THOUGHT i could do

torque,net = I*angular acceleration

and assume that friction is the only torque that's making it slow down ??

I'm so confused..
I think I is (1/3)M,rod*L^2

any help or suggestions would be greatly appreciated.
 
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I is not that, since a ball is attached to the end, I,total would be I of the rod plus M(ball)(L/2)^2
hope it helps
 
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