How Is Work Calculated When a Block Is Pushed Up a Wall?

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Homework Help Overview

The discussion revolves around calculating the work done when a block is pushed up a vertical wall. The problem involves a block with a specified mass, distance, angle of applied force, and friction coefficient, set within the context of classical mechanics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of work done by a force applied at an angle, with initial attempts focusing on gravitational work and friction considerations. Questions arise regarding the interpretation of the problem, particularly whether to include friction in the calculations.

Discussion Status

The discussion is ongoing, with participants clarifying the nature of the work being asked for, including whether it pertains to net work or specific forces. Some participants have expressed confusion about the problem's requirements and are seeking further clarification on calculations.

Contextual Notes

There is a mention of a misunderstanding regarding the problem's requirements, with participants noting the need to distinguish between the work done by the applied force and the net work considering friction.

Idividebyzero
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1. A 2.79 kg block is pushed 1.48 m up a vertical
wall with constant speed by a constant force
of magnitude F applied at an angle of 60.8
with the horizontal.
The acceleration of gravity is 9.8 m/s2 .If the coefficient of kinetic friction between
the block and wall is 0.581, find the work done
by F



2W=FD



3. seems pretty straight foward but i guess I am missing something. first attempt was W= (m)(g)(D)

W= (2.79kg)(9.8m/s^2)(cos(90-60.8))(1.48)
W=35.3J
that answer seems reasonable, but is not correct. first question is only asking what the work done by F is disregarding the friction. next question is about the work done by friction.(
 
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Idividebyzero said:
first question is only asking what the work done by F is disregarding the friction.
I don't understand this comment. In any case, why not start by finding F? (Don't disregard friction!)
 
oh crud. i was getting this problem mixed up with another one no wonder the answer was wrong. it is asking for the net work
 
Last edited:
bump this is the last one giving me problems
 
Idividebyzero said:
it is asking for the net work
The net work done by all forces? No calculation needed for that.

Can you explain the calculation you did in the first post?
 

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