How Long Can a Flywheel-Powered Car Run on Stored Kinetic Energy?

AI Thread Summary
The discussion revolves around calculating the kinetic energy stored in a flywheel-powered car and determining how long the car can run on that energy. The flywheel has a radius of 1.85 m and a mass of 678 kg, with a rotational speed of 3610 rev/min, yielding a kinetic energy of approximately 82,905,778 J. To find the runtime based on a power output equivalent to a 7.9 hp motor, participants suggest converting horsepower to watts for accurate calculations. The relationship between power and time is crucial for determining how long the car can operate before needing to recharge the flywheel. The conversation highlights the importance of understanding rotational dynamics and energy conversion in this context.
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Homework Statement



A car is designed to get its energy from a rotating flywheel with a radius of 1.85 m and a mass of 678 kg. Before a trip, the flywheel is attached to an electric motor, which brings the flywheel's rotational speed up to 3610 rev/min. Find the kinetic energy stored in the flywheel. Answer in units of J.

If the flywheel is to supply energy to the car as would a 7.9hp motor, how long could the car run before the flywheel would have to be brought back up to speed? Answer in units of h.

Homework Equations



rotational KE= 1/2 I \omega2
I=1/2mr2
\omega=\omegao + \alphat
\theta-\thetao=\omegaot+1/2\alphat2

The Attempt at a Solution



I found part 1 which was 82905777.99J but am stuck on how to approach part 2. I think I should use a rotational equation but I don't know angular position nor angular acceleration. Since they give me 7.9hp, I think I should convert it to work (1hp=746W) but don't know what to do with it. Any direction to take would be helpful.
 
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Hi ba726,

ba726 said:

Homework Statement



A car is designed to get its energy from a rotating flywheel with a radius of 1.85 m and a mass of 678 kg. Before a trip, the flywheel is attached to an electric motor, which brings the flywheel's rotational speed up to 3610 rev/min. Find the kinetic energy stored in the flywheel. Answer in units of J.

If the flywheel is to supply energy to the car as would a 7.9hp motor, how long could the car run before the flywheel would have to be brought back up to speed? Answer in units of h.

Homework Equations



rotational KE= 1/2 I \omega2
I=1/2mr2
\omega=\omegao + \alphat
\theta-\thetao=\omegaot+1/2\alphat2

The Attempt at a Solution



I found part 1 which was 82905777.99J but am stuck on how to approach part 2. I think I should use a rotational equation but I don't know angular position nor angular acceleration. Since they give me 7.9hp, I think I should convert it to work (1hp=746W)

This is not converting to work; it is changing the units: that is, changing a power of 7.9 horsepower to the same power in units of watts.

Once you have the power in watts, what is the relationship between power and time?
 
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